Question

От 1 пристани одновременно в противоположных направлениях отплыли два катера средняя скорость одного на 10 километров час больше чем другого через 2 часа расстояние между катерами равнялась 140 километров с какой скоростью двигался

Answer 1

Пусть:
Х км/час -скорость одного катера
Х+10 км/час -скорость второго
2 час-время одного и другого
140км -между ними через 2часа
S=v*t
тогда:
Х*2 +( х+10)*2 =140

2х +(х+10)*2 =140 2х+ 2х+20 =140
4х+ 20 =140
4х= 140-20
4х=120
Х=120:4
Х=30км/час -скорость одного катера
Х+10=30+10=40км/час -скорость другого
проверка:
2х+(х+10)*2=140
2*30+2*30+20=60+60+20=140км
ответ:скорость одного30км/час,другого40км/час

Answer 2

Problem Analysis

We have two boats that depart simultaneously from the same dock in opposite directions. The speed of one boat is 10 kilometers per hour faster than the other. After 2 hours, the distance between the boats is 140 kilometers. We need to find the speed at which the boats are moving.

Solution

Let's assume the speed of the slower boat is x kilometers per hour. Therefore, the speed of the faster boat will be x + 10 kilometers per hour.

After 2 hours, the slower boat will have traveled a distance of 2x kilometers, and the faster boat will have traveled a distance of 2(x + 10) kilometers.

The sum of these distances is equal to the total distance between the boats, which is 140 kilometers. Therefore, we can write the equation:

2x + 2(x + 10) = 140

Simplifying the equation:

2x + 2x + 20 = 140

4x + 20 = 140

4x = 120

x = 30

Therefore, the speed of the slower boat is 30 kilometers per hour, and the speed of the faster boat is 40 kilometers per hour.

Answer

The slower boat was moving at a speed of 30 kilometers per hour, and the faster boat was moving at a speed of 40 kilometers per hour.