Question

Число 12 Хитрун множить або ділить на 2 або 3. Отримане число він знову множить або ділить на 2 або 3 і так загалом 60 разів поспіль. Який результат із запропонованих у відповідях не зможе отримати Хитрун?

Answer 1

Пропущены варианты ответа: а.12, б.18, в.36, г.72,
 д.108

А) *2, затем :2 — и так всего 30 раз, получим = 12.
Б) /2, затем *3 — будет 18, а затем снова *2/2 28 раз
В) Не получится получить число 36.
Г) *3, затем *2 — будет 72, а затем снова *2/2 28 раз
Д) *3, затем *3 — будет 108, а затем снова *2/2 28 раз

Ответ: В) 36

Answer 2

The Problem

The problem states that the number 12 is either multiplied or divided by 2 or 3 repeatedly for a total of 60 times. The question asks which of the given answers cannot be obtained as a result.

Solution

To solve this problem, we need to determine the possible outcomes of multiplying or dividing 12 by 2 or 3 repeatedly for 60 times. Let's calculate the possible results step by step:

1. Multiply 12 by 2: 12 * 2 = 24 2. Multiply 24 by 2: 24 * 2 = 48 3. Multiply 48 by 2: 48 * 2 = 96 4. Divide 96 by 2: 96 / 2 = 48 5. Divide 48 by 2: 48 / 2 = 24 6. Divide 24 by 2: 24 / 2 = 12 7. Divide 12 by 2: 12 / 2 = 6 8. Divide 6 by 2: 6 / 2 = 3 9. Divide 3 by 3: 3 / 3 = 1

As we can see, after 9 steps, we reach the number 1. From this point, any further multiplication or division by 2 or 3 will not change the result, as any number multiplied or divided by 1 remains the same.

Therefore, after 60 steps, the result will be the same as after 9 steps, which is 1. So, the number 1 is the only possible outcome that can be obtained after 60 steps of multiplying or dividing 12 by 2 or 3.

Conclusion

Based on the calculations, the result that cannot be obtained from the given answers is 1.