Question

Два зайца,столкнувшись,испугались и побежали в противоположные стороны так,что через8 секунд между ними было 200м.Один заяц бежал со скоростью 12м/с.Определи скорость другого зайца.

Answer 1

1)12*8=96(м)-расстояние 1 зайца
2)200-96=104(м)-расстояние 2 зайца
3)104:8=13(м/ч)-скорость 2 зайца
Ответ :13м/ч скорость 2 зайца

Answer 2

12*8=96
200-96=104
104/8=13 м/с

Answer 3

Problem Analysis

Two hares collided, got scared, and ran in opposite directions. After 8 seconds, there was a distance of 200 meters between them. One hare ran at a speed of 12 m/s. We need to determine the speed of the other hare.

Solution

Let's assume the speed of the second hare is v m/s.

Since both hares are running in opposite directions, the total distance covered by both hares is equal to the distance between them, which is 200 meters.

The first hare runs for 8 seconds at a speed of 12 m/s, so the distance covered by the first hare is:

Distance1 = Speed1 × Time1 = 12 m/s × 8 s = 96 meters

The second hare also runs for 8 seconds, so the distance covered by the second hare is:

Distance2 = Speed2 × Time2 = v m/s × 8 s = 8v meters

The total distance covered by both hares is equal to the distance between them:

Distance1 + Distance2 = 200 meters

Substituting the values of Distance1 and Distance2, we get:

96 meters + 8v meters = 200 meters

Simplifying the equation:

8v = 200 - 96

8v = 104

v = 104 / 8

v = 13 meters per second

Therefore, the speed of the second hare is 13 m/s.

Answer

The speed of the second hare is 13 m/s.