Question

3cd( 4c-d)+4cd(d-3c) c=10, d=-5

Answer 1

3cd(4c-d)+4cd(d-3c)=12c²d-3cd²+4cd²-12c²d=cd²
cd², если c=10, d=-5, то 10*(-5)²=10*25=250

Answer 2

I can help you with your math problem. Here is the detailed solution:

First, substitute the value of $d$ into the equation:

$$3c(-5)(4c-(-5))+4c(-5)(-5-3c)+c=10$$

Then, simplify the equation by expanding the brackets and collecting like terms:

$$-60c^2+75c+100c^2+100c-25-60c^2-75c+c=10$$

$$-20c^2+c-15=10$$

Finally, solve for $c$ by moving all the terms to one side and using the quadratic formula:

$$-20c^2+c-25=0$$

$$c=\frac{-1\pm\sqrt{1-4(-20)(-25)}}{-40}$$

$$c=\frac{-1\pm\sqrt{-1999}}{-40}$$

Therefore, the solution is:

$$c=\frac{-1\pm i\sqrt{1999}}{-40}$$

where $i$ is the imaginary unit.Ответь+подробно.+3cd(+4c-d)+4cd(d-3c)+c=10,+d=-5