Question

От Москвы до Пскова 760км.Поезд вышел из Москвы в 19ч. и шел 6ч со скоростью 60км/ч.С какой скоростью прошел поезд остальной путь, если он прибыл в Псков в 9ч утра, при этом 3ч в пути он потратил на остановки?

Answer 1

1) 60*6=360 км за 6 ч 2) 760-360=400 км осталось проехать 3) 19+6=25ч(т е в 1ч ночи начался остальной путь) 4) 9-1-3=5ч на остальной путь 5) 400км:5ч=80 км/ч с такой скоростью поошел поезд остальной путь

Answer 2

Calculation of the Train's Speed

To determine the speed at which the train traveled for the remaining distance, we can use the formula: speed = distance / time.

Given that the total distance from Moscow to Pskov is 760 km and the train traveled for 6 hours at a speed of 60 km/h, we can calculate the distance covered during this time: distance = speed * time = 60 km/h * 6 h = 360 km.

Therefore, the train covered 360 km in the first 6 hours.

To find the remaining distance, we subtract the distance covered in the first 6 hours from the total distance: remaining distance = total distance - distance covered = 760 km - 360 km = 400 km.

Now, we need to find the time it took for the train to cover the remaining distance. We know that the train arrived in Pskov at 9 AM and spent 3 hours on stops. Therefore, the time spent traveling is 9 AM - 3 hours = 6 AM.

The train left Moscow at 7 PM, which means it traveled for 6 AM - 7 PM = 11 hours.

To calculate the speed at which the train covered the remaining distance, we use the formula: speed = distance / time = 400 km / 11 h ≈ 36.36 km/h.

Therefore, the train traveled at a speed of approximately 36.36 km/h for the remaining distance from Moscow to Pskov.