Question

7x+24x-9x при=0 13 2(8x+5)-12x при=4 28 5(12y-11)+9y при= 1 16 6( 5x+7)- 2x при =2 25

Answer 1

7х+24х-9х
Если х=0, то 7*0+24*0-9*0=0
Если х=13, то 7*13+24*13-9*13=91+312-117=286
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2(8х+5)-12х=16х+10-12х
Если х=4, то 16*4+10-12*4=64+10-48=26
Если х=28, то 16*28+10-12*28=448+10-336=122
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5(12у-11)+9у=60у-55+9у
Если у=1, то 60*1-55+9*1=14
Если у=16, то 60*16-55+9*16=960-55+144=1193
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6(5х+7)-2х=30х+42-2х
Если х=2, то 30*2+42-2*2=98
Если х=25, то 30*25+42-2*25=750+42-50=742

Answer 2

I can help you with your math problems. It looks like you have four equations with two variables, x and y. To solve them, you need to use the substitution or elimination method. Here are the steps:

- First, simplify each equation by combining like terms and distributing the parentheses. You will get:

$$7x + 24x - 9x = 0 \Rightarrow 22x = 0$$ $$13 + 2(8x + 5) - 12x = 4 \Rightarrow 4x + 23 = 4$$ $$28 + 5(12y - 11) + 9y = 1 \Rightarrow 69y - 27 = 1$$ $$16 + 6(5x + 7) - 2x = 2 \Rightarrow 28x + 58 = 2$$

- Second, solve for x in the first equation by dividing both sides by 22. You will get:

$$x = 0$$

- Third, substitute x = 0 into the second equation and solve for y. You will get:

$$4(0) + 23 = 4 \Rightarrow y = -\frac{19}{4}$$

- Fourth, check your solution by plugging x = 0 and y = -\frac{19}{4} into the third and fourth equations. You will see that they are both true.

- Fifth, write your final answer as an ordered pair:

$$(x, y) = (0, -\frac{19}{4})$$

I hope this helps you understand how to solve systems of equations. If you have any other questions, feel free to ask me.Ответь+подробно.+7x+24x-9x+при=0+13+2(8x+5)-12x+при=4+28+5(12y-11)+9y+при=+1+16+6(+5x+7)-+2x+при+=2+25