Question

Ширина прямоугольника равна 8 дм что состовляет 1/3 часть его длины найди периметр и площадь прямоугольника

Answer 1

А=8
б=8*3(т.к. а=1/3б)=24
p=2*(8+24)=64
s=24*8=192

Answer 2

Problem Analysis

We are given that the width of a rectangle is 8 dm, which is equal to 1/3 of its length. We need to find the perimeter and area of the rectangle.

Solution

Let's start by finding the length of the rectangle.

From the given information, we know that the width of the rectangle is 8 dm and it is equal to 1/3 of its length. Therefore, we can set up the equation:

width = 1/3 * length

Substituting the value of the width, we have:

8 = 1/3 * length

To find the length, we can multiply both sides of the equation by 3:

3 * 8 = length

Simplifying, we get:

length = 24 dm

Now that we have the length and width of the rectangle, we can find its perimeter and area.

Perimeter of the Rectangle

The perimeter of a rectangle is given by the formula:

perimeter = 2 * (length + width)

Substituting the values, we have:

perimeter = 2 * (24 + 8) = 2 * 32 = 64 dm

Therefore, the perimeter of the rectangle is 64 dm.

Area of the Rectangle

The area of a rectangle is given by the formula:

area = length * width

Substituting the values, we have:

area = 24 * 8 = 192 dm^2

Therefore, the area of the rectangle is 192 dm^2.

Summary

Given that the width of the rectangle is 8 dm, which is equal to 1/3 of its length, we have found the following:

- Length of the rectangle: 24 dm - Perimeter of the rectangle: 64 dm - Area of the rectangle: 192 dm^2

Please let me know if there is anything else I can help you with!