Question

Из 2-х пунктов,расстояние между которыми 7 км 500 м, одновременно в одном направлении вышел пешеход со скоростью 6 км/ч и выехал автобус.Определите скорость автобуса,если он догнал пешехода через 15 мин.Помогите пожалуйста!Заранее спасибо)))

Answer 1

15 мин=0,25 часа

7 км500м=7,5 км

решаем:

1)6*0,25=1,5 км прошёл пешеход за 15 мин

2)7,5+1,5=9 км нужно преодолеть автобусу

3)9:0,25=36 км/час скорость автобуса

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Answer 2

решение

15мин=0,2час

6*0,2=1,2

6*1,2=7,2км

Answer 3

Problem Analysis

We are given that there are two points with a distance of 7 km 500 m between them. A pedestrian starts walking from one point with a speed of 6 km/h, while a bus starts moving from the same point. We need to determine the speed of the bus if it catches up to the pedestrian in 15 minutes.

Solution

To solve this problem, we can use the formula:

Distance = Speed × Time

Let's assume the speed of the bus is v km/h. The pedestrian's speed is given as 6 km/h. We know that the distance between the two points is 7 km 500 m, which is equivalent to 7.5 km.

The time taken by the bus to catch up to the pedestrian is given as 15 minutes, which is equivalent to 0.25 hours.

We can set up the following equation:

Distance covered by the bus = Distance covered by the pedestrian

v × 0.25 = 6 × 0.25

Simplifying the equation, we get:

v = 6

Therefore, the speed of the bus is 6 km/h.

Conclusion

The speed of the bus is 6 km/h.