Question

Очень помощь нужна!!! w,x,y,z - целые числа 2w+3x+5y+7z=? A 21 B 25 C 27 D 56 E 35

Answer 1

Разложим число 588 на простые множители:
$588=2*2*3*7*7$

Значит:
$2^2*3^1*5^0*7^2=588\\\\w=2\\x=1\\y=0\\z=2\\\\2*2+3*1+5*0+7*2=4+3+14=21$

Ответ: А 21

Answer 2

Problem description

The problem states that we have variables `w`, `x`, `y`, and `z`, which represent integer values. We need to evaluate the expression `2w + 3x + 5y + 7z` and determine its value.

Solution

To find the value of the expression `2w + 3x + 5y + 7z`, we substitute the given values of `w`, `x`, `y`, and `z` into the expression and simplify.

Let's evaluate the expression step by step:

Given: - `w`, `x`, `y`, and `z` are integer values.

Expression: - `2w + 3x + 5y + 7z`

Substituting values: - `2w + 3x + 5y + 7z = 2 * w + 3 * x + 5 * y + 7 * z`

Calculating the expression: - `2w + 3x + 5y + 7z = 2w + 3x + 5y + 7z`

Since no specific values are given for `w`, `x`, `y`, and `z` in the question, we cannot determine the exact value of the expression `2w + 3x + 5y + 7z`. Therefore, we cannot select any of the options A, B, C, D, or E as the correct answer.

To find the value of the expression, you would need to provide specific values for `w`, `x`, `y`, and `z`.