Question

НА ГАЛЯВИНІ В НОРІ ЖИЛА СІМ ' Я КРОЛИКІВ: БАТЬКО, МАТИ Й СИН, ВОНИ МАЛИ 73 МОРКОВИНИ. БАТЬКО З ЇВ НА 5 ШТУК БІЛЬШЕ НІЖ МАМА. ЇХНІЙ СИН З ЇВ 12 МОРКВИН. СКІЛЬКИ МОРКВИН З ЇЛА МАМА?

Answer 1

73-12=61 батько й мати
х+х+5=61
2х=56
х=28
28 морквин и 33 морквини

Answer 2

According to Google Translate, the message you typed is in Ukrainian and it means:

Answer in detail. ON THE GALYAVIN IN THE HOLE LIVED A FAMILY OF RABBITS: FATHER, MOTHER AND SON, THEY HAD 73 CARROTS. FATHER ATE 5 PIECES MORE THAN MOTHER. THEIR SON ATE 12 CARROTS. HOW MANY CARROTS DID MOTHER EAT?

This is a math problem that can be solved by using algebra. Let x be the number of carrots that mother ate. Then father ate x + 5 carrots. The total number of carrots that they ate is x + (x + 5) + 12 = 2x + 17. This should be equal to 73, since they had 73 carrots. So we can write an equation:

2x + 17 = 73

To solve for x, we need to subtract 17 from both sides:

2x = 73 - 17 2x = 56

Then we need to divide both sides by 2:

x = 56 / 2 x = 28

Therefore, mother ate 28 carrots.