
Реши задачу в первый день туристы были в пути 10 часов, а во второй 7 часов . За второй день пути
туристы преодалели расстояние на 12 км меньше, чем за первый. Сколько километров туристы прошли за эти два дня, если за каждый час движения они преодолевали одинаковое расстояние?

Ответы на вопрос

12:3=4 км/ч
4*10+4*7=68 км
ответ 68 км туристы прошли за два дня



Problem Analysis
To solve this problem, we need to find the total distance traveled by the tourists over two days. We are given that on the first day, they were in transit for 10 hours, and on the second day, they were in transit for 7 hours. We also know that on the second day, they traveled 12 km less than on the first day. Additionally, we are told that the tourists covered the same distance per hour of travel.Solution
Let's denote the distance traveled on the first day as x km. Since the tourists covered the same distance per hour of travel, we can say that the distance traveled on the second day is x - 12 km.To find the total distance traveled over two days, we need to add the distances traveled on each day. Therefore, the total distance is x + (x - 12) km.
Now, let's solve for x using the given information.
Calculation
We know that the tourists were in transit for 10 hours on the first day and covered a distance of x km. Therefore, their speed on the first day was x/10 km/h.Similarly, on the second day, they were in transit for 7 hours and covered a distance of x - 12 km. Therefore, their speed on the second day was (x - 12)/7 km/h.
Since the speed is equal to the distance divided by the time, we can set up the following equation:
x/10 = (x - 12)/7
To solve this equation, we can cross-multiply:
7x = 10(x - 12)
Simplifying further:
7x = 10x - 120
3x = 120
x = 40
Answer
The distance traveled on the first day (x) is 40 km. Therefore, the distance traveled on the second day is x - 12 = 40 - 12 = 28 km.The total distance traveled over two days is 40 + 28 = 68 km.
So, the tourists traveled a total of 68 km over the two days.
Please let me know if you need any further assistance!


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