Question

Два хоккеиста первый забил на 8 шайб больше чем второй. это составляет 20% от шайб забитых их командой. сколько шайб забил первый хоккеист.сколько шайб было забито всего?сколько шайб забил первы хоккеист.забивали только два игрока. решение ОЧЕНЬ СРОЧНО ПОМОГИТЕ ПОЖАЛУЙСТА.

Answer 1

1)8*80:100=получается 6.4, надо его округлить.получаеться 7 .первый хоккеист забил Всего забито; 16:80*100=12.8. округляем до 13

Answer 2

Ответ будет 13 шайб, внизу решение есть

Answer 3

Problem Analysis

We are given that the first hockey player scored 8 more goals than the second player, and this accounts for 20% of the total goals scored by their team. We need to determine how many goals the first player scored, the total number of goals scored, and the number of goals scored by the second player.

Solution

Let's assume the number of goals scored by the second player is x. According to the problem, the first player scored 8 more goals than the second player, so the number of goals scored by the first player is x + 8.

We are also given that the goals scored by the first player and the second player account for 20% of the total goals scored by their team. This means that the sum of their goals is 20% of the total goals.

Let's represent the total number of goals scored by their team as T. According to the problem, the sum of their goals is 20% of T, which can be written as:

(x + 8) + x = 0.2T

Simplifying the equation, we get:

2x + 8 = 0.2T

To solve for x, we need to know the value of T. Unfortunately, the problem does not provide this information. Therefore, it is not possible to determine the exact number of goals scored by the first player, the total number of goals scored, or the number of goals scored by the second player without knowing the value of T.

If you have any additional information or if there is anything else I can assist you with, please let me know!