Question

Велосипедист выехал с постоянной скоростью из города А в город В, расстояние между которыми равно 63 км. На следующий день он отправился обратно со скоростью на 2 км/ч больше прежней. По дороге он сделал остановку на 2 часа. В результате он затратил на обратный путь столько же времени, сколько на путь из А в В. Найдите скорость велосипедиста на пути из А в В. Ответ дайте в км/ч.

Answer 1

Думаю, что всё верно) 
простите за почеркушки ^^

Answer 2

Problem Analysis

A cyclist travels from city A to city B at a constant speed. The distance between the two cities is 63 km. On the next day, the cyclist returns from city B to city A at a speed that is 2 km/h faster than the previous day. The cyclist makes a 2-hour stop on the way back. The total time taken for the return trip is the same as the time taken for the trip from city A to city B. We need to find the speed of the cyclist on the trip from city A to city B.

Solution

Let's assume the speed of the cyclist on the trip from city A to city B is x km/h.

The time taken for the trip from city A to city B is given by the formula time = distance / speed. Therefore, the time taken for the trip from city A to city B is 63 / x hours.

On the return trip, the cyclist's speed is (x + 2) km/h. The time taken for the return trip is the same as the time taken for the trip from city A to city B, plus the 2-hour stop. Therefore, the time taken for the return trip is 63 / (x + 2) + 2 hours.

According to the problem, the time taken for the return trip is the same as the time taken for the trip from city A to city B. So we can set up the equation:

63 / x = 63 / (x + 2) + 2

To solve this equation, we can cross-multiply and simplify