Question

Из двух поселков, расстояние между которыми 2км, выехали одновременно два велосипедиста. Через 30 мин первый велосипедист догнал второго. С какой скоростью мог двигаться один из велосипедистов, если другой двигался со скоростью 12км/ч ? Помогите решить.

Answer 1

30мин=0.5 часов

12*0.5=6км проехал 1ый велосип.

6-2=4км проехал 2ой велосип.

4:0.5=8км/ч скорость 2ого велосип.

 Ответ:8 км/ч.

 

 

 

 

 

Answer 2

30мин=0.5 часов

12*0.5=6км проехал 1-ый велосип.

6-2=4км проехал 2-ой велосип.

4:0.5=8км/ч скорость 2-ого велосип.

 Ответ:8 км/ч.

Answer 3

Problem Analysis

We have two cyclists who start from two villages that are 2 km apart. One cyclist is moving at a speed of 12 km/h. After 30 minutes, the first cyclist catches up to the second cyclist. We need to determine the speed at which the other cyclist is moving.

Solution

Let's assume the speed of the second cyclist is x km/h.

We know that the distance traveled by both cyclists is the same when the first cyclist catches up to the second cyclist. The distance traveled by the first cyclist is the product of their speed and time, which is 12 km/h * 0.5 h = 6 km.

Since the distance between the two villages is 2 km, the second cyclist must have traveled 2 km less than the first cyclist. Therefore, the distance traveled by the second cyclist is 6 km - 2 km = 4 km.

We can now set up the equation:

Distance = Speed * Time

For the first cyclist: 6 km = 12 km/h * 0.5 h

For the second cyclist: 4 km = x km/h * 0.5 h

Simplifying the equations:

6 = 12 * 0.5

4 = x * 0.5

Solving for x:

4 = x * 0.5

x = 4 / 0.5

x = 8 km/h

Therefore, the speed of the second cyclist is 8 km/h.

Answer

The second cyclist could be moving at a speed of 8 km/h.