Question

Петя заполнил клетки таблицы числами так, что сумма чисел, стоящих в любых трёх подряд идущих клетках, равнялась 15, а двоечник Колька стёр почти все числа. Сможете ли вы восстановить таблицу?7 3 сколько пробелов столько и пропущенных а пропущенных 11 вродепомогите плизззззззззззззззз

Answer 1

В роди бы так должно быть
7.5.3
6.1.8
2.9.4

Answer 2

Problem Description

Петя заполнил клетки таблицы числами так, что сумма чисел, стоящих в любых трёх подряд идущих клетках, равнялась 15, а двоечник Колька стёр почти все числа. Требуется восстановить таблицу.

Solution

To solve this problem, we need to find a combination of numbers that satisfies the given conditions. Let's start by analyzing the information provided.

We know that the sum of any three consecutive cells should be equal to 15. Additionally, Kolya erased almost all the numbers, leaving only a few. We need to determine the missing numbers and fill in the table.

Let's consider the possible combinations of three consecutive cells that add up to 15:

- 7 + 3 + 5 = 15 - 3 + 5 + 7 = 15 - 5 + 7 + 3 = 15

Based on these combinations, we can start filling in the table. Since Kolya erased most of the numbers, we will use the available information to determine the missing numbers.

Let's assume that the table has three rows and three columns. We will use the following notation to represent the cells:

a b c
d e f
g h i

Using the combinations mentioned above, we can fill in some of the cells:

7 3 5
_ _ _
_ _ _
_ _ _

Now, let's analyze the information about the missing numbers. The user mentioned that there are as many missing numbers as there are spaces. Since there are 11 spaces mentioned, we can assume that there are 11 missing numbers.

To distribute the missing numbers, we can start from the top-left corner and move row by row, filling in the missing numbers. We will use the numbers 1 to 9 for the missing numbers.

7 3 5
1 2 3
4 5 6

Now, let's check if the sum of any three consecutive cells is equal to 15:

- 7 + 3 + 5 = 15 (top row) - 3 + 5 + 1 = 9 (top row) - 5 + 1 + 2 = 8 (top row) - 1 + 2 + 3 = 6 (middle row) - 2 + 3 + 4 = 9 (middle row) - 3 + 4 + 5 = 12 (middle row) - 4 + 5 + 6 = 15 (bottom row)

The sum of any three consecutive cells is not equal to 15 in some cases. Therefore, the current arrangement does not satisfy the given conditions. We need to try a different arrangement.

Let's try another combination:

- 7 + 3 + 5 = 15 - 3 + 5 + 7 = 15 - 5 + 7 + 3 = 15

Using this combination, we can fill in the table as follows:

7 3 5
_ _ _
_ _ _
_ _ _

Now, let's distribute the missing numbers:

7 3 5
1 2 9
4 5 6

Let's check if the sum of any three consecutive cells is equal to 15:

- 7 + 3 + 5 = 15 (top row) - 3 + 5 + 1 = 9 (top row) - 5 + 1 + 2 = 8 (top row) - 1 + 2 + 9 = 12 (middle row) - 2 + 9 + 4 = 15 (middle row) - 9 + 4 + 5 = 18 (middle row) - 4 + 5 + 6 = 15 (bottom row)

The sum of any three consecutive cells is not equal to 15 in some cases. Therefore, this arrangement also does not satisfy the given conditions.

Based on the information provided, it is not possible to determine a unique solution for the table. The missing numbers and their arrangement are not specified, making it impossible to accurately reconstruct the table.

Please note that the information provided is limited, and without additional details, it is not possible to determine the exact solution.

I hope this explanation helps! Let me know if you have any further questions.