Question

В кассе лежит 98 монет по 1,2 и 5 рублей.Монет по 2 руб на 10 больше чем по 1-му рублю,а по 5 в 7 раз больше чем по 2 рубля.Сколько в кассе монет каждого номинала ?

Answer 1

Пусть х монеты по 1 руб, монеты 2 руб   х+10, монеты 5 руб 7(х+10)
х+(х+10)+7(х+10)=98
х+х+10+7х+70=98
9х+80=98
9х=98-80
9х=18
х=2 кол.во монет по 1 руб
2+10=12 кол.во монет по 2 руб
7(2+10)=84 кол.во монет по 5 руб

Answer 2

I can answer your question in detail. You have a math problem about the number of coins in a cash register. Let me show you how to solve it step by step.

First, let us introduce some variables to represent the unknown quantities. Let x be the number of coins of 1 ruble, y be the number of coins of 2 rubles, and z be the number of coins of 5 rubles. Then, we can write the following equations based on the given information:

x + y + z = 98 (the total number of coins is 98) y = x + 10 (the number of coins of 2 rubles is 10 more than the number of coins of 1 ruble) z = 7y (the number of coins of 5 rubles is 7 times the number of coins of 2 rubles)

Now, we have a system of three equations with three unknowns. We can use the substitution method to solve it. First, we can substitute y with x + 10 in the second and third equations:

x + (x + 10) + z = 98 z = 7(x + 10)

Then, we can substitute z with 7(x + 10) in the first equation:

x + (x + 10) + 7(x + 10) = 98

Simplifying and solving for x, we get:

x = 2

Now, we can plug x = 2 into the second equation to find y:

y = x + 10 y = 2 + 10 y = 12

Finally, we can plug y = 12 into the third equation to find z:

z = 7y z = 7 * 12 z = 84

Therefore, the number of coins of 1 ruble is 2, the number of coins of 2 rubles is 12, and the number of coins of 5 rubles is 84. This is the answer to your question.

I hope this explanation was clear and helpful. If you want to learn more about solving systems of equations, you can check out some of the web search results I found for you . Have a nice day!