Question

Равлик за день піднімаеться на 4м вгору а за ніч спускаеться на 2м вниз.За скільки днів він підніметься вершину дерева висота якого 10м

Answer 1

За день равлик піднімаеться на 4м - 2м = 2м, отже 10 м він подолає за 10/2 =  5днів

Answer 2

4-2=2м за 1день
10:2=5дней

Answer 3

Problem Analysis

To solve this problem, we need to determine how many days it will take for a snail to reach the top of a tree. The snail climbs 4 meters during the day and descends 2 meters during the night. The height of the tree is given as 10 meters.

Solution

Let's break down the problem step by step:

1. During the day, the snail climbs 4 meters. 2. During the night, the snail descends 2 meters. 3. The snail repeats this pattern every 24 hours.

To find out how many days it will take for the snail to reach the top of the tree, we can calculate the number of cycles it will take for the snail to climb a total of 10 meters.

Calculation

Each cycle consists of a day and a night, during which the snail climbs 4 meters and descends 2 meters, respectively. Therefore, each cycle covers a net distance of 4 - 2 = 2 meters.

To reach a total height of 10 meters, the snail needs to complete 10 / 2 = 5 cycles.

Since each cycle takes 24 hours, the snail will take 5 * 24 = 120 hours to reach the top of the tree.

Answer

Therefore, it will take the snail 5 days to reach the top of the tree, assuming the snail maintains a consistent climbing and descending pattern.

Please note that this calculation assumes the snail starts at the base of the tree and does not encounter any obstacles or interruptions during its climb.