Question

Если открыть одновременно первую и вторую трубы то пустой бассейн наполнится за 10 часов одна Первая труба наполняет пустой бассейн за 14 часов За сколько часов наполняет пустой бассейн одна вторая труба

Answer 1

1- объем бассейна
1/1,5=10/15=2/3- совместная производительность
1/2,5=10/25=2/5- производительность 1й трубы
2/3-2/5=10/15-6/15=4/15- - производительность 2й трубы

1:4/15=1*15/4=3,75ч- За столько часов наполняет пустой бассейн одна вторая труба

Answer 2

Problem Analysis

We are given two pipes, and we need to determine how long it takes for the second pipe to fill an empty pool. We know that if both pipes are opened simultaneously, the pool will be filled in 10 hours. We also know that the first pipe alone can fill the pool in 14 hours. We need to find the time it takes for the second pipe to fill the pool on its own.

Solution

Let's assume that the second pipe can fill the pool in x hours.

From the given information, we can deduce the following: - If both pipes are opened simultaneously, the pool is filled in 10 hours. - The first pipe alone can fill the pool in 14 hours.

To solve this problem, we can use the concept of rates. The rate at which the first pipe fills the pool is 1/14 of the pool per hour, and the rate at which both pipes fill the pool is 1/10 of the pool per hour.

Let's calculate the rates for both pipes: - The rate at which the first pipe fills the pool is 1/14 of the pool per hour. - The rate at which both pipes fill the pool is 1/10 of the pool per hour.

Since the rates are additive, we can subtract the rate of the first pipe from the rate of both pipes to find the rate of the second pipe: - The rate of the second pipe is 1/10 - 1/14 of the pool per hour.

Now, we can set up an equation to find the time it takes for the second pipe to fill the pool on its own: - Let x be the time it takes for the second pipe to fill the pool on its own. - The rate of the second pipe is 1/x of the pool per hour.

Setting up the equation: 1/x = 1/10 - 1/14

To solve for x, we can find the least common denominator (LCD) of 10 and 14, which is 70: 1/x = (7/70) - (5/70) 1/x = 2/70

Cross-multiplying: 70 = 2x x = 70/2 x = 35

Therefore, it takes the second pipe 35 hours to fill the pool on its own.

Answer

The second pipe will fill the empty pool in 35 hours if it is opened alone.