Question

В соревнованиях по плаванию учавствовало 74 ученика из трёх школ.Из второй школы в соревнованиях учавствовало спортсменов в 2 раза больше, чем из первой, а из третьей- на 9 спортсменов больше, чем из второй. Сколько спортсменов уравствовало в соревнованиях по плаванию из каждой школы?Помогите плиз)

Answer 1

Х+2х+2х+9=74
5х=74-9
5х=65
х=65:5
х=13- учеников из первой школы
2*13=26-учеников из второй школы
2*13+9=35- учеников из третьей школы

Answer 2

Solution:

Let's solve this step by step.

1. Total Number of Participants: - The total number of participants in the swimming competition is 74.

2. Participants from the Second School: - The number of participants from the second school is twice the number of participants from the first school.

3. Participants from the Third School: - The number of participants from the third school is 9 more than the number of participants from the second school.

Calculation:

Let's denote: - The number of participants from the first school as x. - The number of participants from the second school as 2x (twice the number from the first school). - The number of participants from the third school as 2x + 9 (9 more than the number from the second school).

The total number of participants is the sum of participants from all three schools: x + 2x + (2x + 9) = 74

Solving for x: 5x + 9 = 74 5x = 65 x = 13

Answer:

So, the number of participants from each school is: - First School: 13 participants - Second School: 26 participants - Third School: 35 participants

This satisfies the given conditions and adds up to a total of 74 participants.