Question

Заполните таблицу: 1)у=3х-2 Х:-1,0 У:_,_ 2)у=1/2х+3 х:0,2 у:_,_ 3)у=2х-3 х:1,3 у:_,_ 4)у=-5х+4 х:0,2 у:_,_ Помогите плиз,заранее спасибо)))

Answer 1

1)y=-5;-2
2)y=3;4
3)y=-1;3
4)y=4;-6

Answer 2

Table Filling:

| Equation | x | y | |----------|---|---| | 1) y = 3x - 2 | -1 | 1 | | 1) y = 3x - 2 | 0 | -2 | | 2) y = 1/2x + 3 | 0 | 3 | | 2) y = 1/2x + 3 | 2 | 4 | | 3) y = 2x - 3 | 1 | -1 | | 3) y = 2x - 3 | 3 | 3 | | 4) y = -5x + 4 | 0 | 4 | | 4) y = -5x + 4 | 2 | -6 |

Solution:

To fill in the table, we need to substitute the given values of x into the equations and solve for y.

1) For the equation y = 3x - 2: - When x = -1, y = 3(-1) - 2 = -5. - When x = 0, y = 3(0) - 2 = -2.

2) For the equation y = 1/2x + 3: - When x = 0, y = 1/2(0) + 3 = 3. - When x = 2, y = 1/2(2) + 3 = 4.

3) For the equation y = 2x - 3: - When x = 1, y = 2(1) - 3 = -1. - When x = 3, y = 2(3) - 3 = 3.

4) For the equation y = -5x + 4: - When x = 0, y = -5(0) + 4 = 4. - When x = 2, y = -5(2) + 4 = -6.

Therefore, the filled table is as follows:

| Equation | x | y | |----------|---|---| | 1) y = 3x - 2 | -1 | -5 | | 1) y = 3x - 2 | 0 | -2 | | 2) y = 1/2x + 3 | 0 | 3 | | 2) y = 1/2x + 3 | 2 | 4 | | 3) y = 2x - 3 | 1 | -1 | | 3) y = 2x - 3 | 3 | 3 | | 4) y = -5x + 4 | 0 | 4 | | 4) y = -5x + 4 | 2 | -6 |

I hope this helps! Let me know if you have any further questions.