Question

У Максима в 2 раза больше марок,чем у Глеба.Всего у них 3 набора по 5 марок и 4 набора по 3 марки.Сколько марок у каждого.

Answer 1

3×5+4×3=27(м) всего
27÷3=9(м) у Глеба
9×2=18(м) у Максима

Answer 2

Problem Analysis

We are given that Maxim has twice as many stamps as Gleb. They both have a total of 3 sets of 5 stamps and 4 sets of 3 stamps. We need to determine how many stamps each of them has.

Solution

Let's assume that Gleb has x stamps. Since Maxim has twice as many stamps as Gleb, Maxim will have 2x stamps.

We know that they have a total of 3 sets of 5 stamps and 4 sets of 3 stamps. Each set contains the same number of stamps.

The total number of stamps in the sets of 5 stamps is 3 * 5 = 15 stamps. The total number of stamps in the sets of 3 stamps is 4 * 3 = 12 stamps.

Therefore, the total number of stamps they have is 15 + 12 = 27 stamps.

We can set up the following equation to represent the total number of stamps they have:

x + 2x = 27

Simplifying the equation, we get:

3x = 27

Dividing both sides of the equation by 3, we find:

x = 9

Therefore, Gleb has 9 stamps and Maxim has 2 * 9 = 18 stamps.

Answer

Gleb has 9 stamps and Maxim has 18 stamps.