
Стороны основания правильной четырехугольной пирамиды равны 4 см и 8 см а высота равна 12 см. РЕШИТЕ


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Given Information
We are given that the sides of a right quadrilateral pyramid are equal to 4 cm and 8 cm, and the height is 12 cm.Solution
To solve this problem, we can use the Pythagorean theorem and the formula for the volume of a pyramid.Step 1: Finding the Base Since the pyramid is right, we can use the Pythagorean theorem to find the length of the base. Let's denote the sides of the base as a and b, where a = 4 cm and b = 8 cm. The height of the pyramid is the perpendicular distance from the apex to the base. Using the Pythagorean theorem, we have:
a^2 + b^2 = h^2
Substituting the given values, we get:
4^2 + 8^2 = h^2
Simplifying, we find:
16 + 64 = h^2
80 = h^2
Taking the square root of both sides, we get:
h = √80
h = 4√5 cm
So, the height of the pyramid is 4√5 cm.
Step 2: Finding the Volume The volume of a pyramid can be calculated using the formula:
Volume = (1/3) * base area * height
The base area of a quadrilateral pyramid can be calculated by dividing it into two triangles and finding the area of each triangle. Since the base is a right quadrilateral, the triangles will be right triangles.
The area of a right triangle can be calculated using the formula:
Area = (1/2) * base * height
Let's calculate the base area of the pyramid:
Base Area = (1/2) * a * b
Substituting the given values, we get:
Base Area = (1/2) * 4 cm * 8 cm
Base Area = 16 cm^2
Now, let's calculate the volume of the pyramid:
Volume = (1/3) * Base Area * height
Substituting the values we found, we get:
Volume = (1/3) * 16 cm^2 * 4√5 cm
Simplifying, we find:
Volume = (16/3) * √5 cm^3
So, the volume of the pyramid is (16/3) * √5 cm^3.
Answer
Therefore, the sides of the base of the pyramid are 4 cm and 8 cm, and the height is 12 cm. The volume of the pyramid is (16/3) * √5 cm^3.

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