Question

Першого дня супермаркет електроніки продав 112 мо- більних телефонів, що на 5 телефонів менше, ніж вінпродав другого дня, і на 13 телефонів більше, ніж про-дав третього дня. Скільки телефонів продав супермар-кет за три дні?​

Answer 1

Ответ:

238 телефонів

Пошаговое объяснение:

2-го дня продали на 5 більше ніж першого = 112 +5 = 117 тел.

3-го дня продали на 13 менше ніж першого = 112 - 13 = 99 тел.

за три дні: 112 + 117 + 99 = 238 телефонів

Answer 2

According to Google Translate, the Ukrainian text you entered means:

Answer in detail. On the first day, the electronics supermarket sold 112 mobile phones, which is 5 phones less than it sold on the second day, and 13 phones more than it sold on the third day. How many phones did the supermarket sell in three days?

To solve this problem, we can use the following steps:

- Let x be the number of phones sold on the second day. - Then, the number of phones sold on the first day is x - 5, and the number of phones sold on the third day is x - 18 (since 13 phones more than x - 18 is x - 5). - The total number of phones sold in three days is x + (x - 5) + (x - 18) = 3x - 23. - We know that the number of phones sold on the first day is 112, so we can substitute x - 5 = 112 and solve for x. - x - 5 = 112 - x = 112 + 5 - x = 117 - Therefore, the number of phones sold on the second day is 117, and the number of phones sold on the third day is 117 - 18 = 99. - The total number of phones sold in three days is 3x - 23 = 3(117) - 23 = 351 - 23 = 328.

The answer is 328 phones.