Question

3. На лугу паслись гуси и козы. Дима посчитал с ноги, получилось 10 ног. Напиши, сколько могло быть гусейи сколько коз.1) гуси:КОЗЫ:КОЗЫ:2) гуси​

Answer 1

Ответ:

Могло быть 2 козы и 1 гусь, и также могла быть 1 коза и 3 гуся

Answer 2

Пошаговое объяснение:

1 коза

10-4=6

6:2=3 гуся

2 козы

10-8=2

2:2=1 гусь

Могло быть:

1 коза и 3 гуся

2 козы и 1 гусь

Answer 3

Problem Analysis

In this problem, we are given that there are geese and goats grazing in a meadow. The total number of legs counted by Dima is 10. We need to determine how many geese and how many goats there could be.

Solution

Let's assume that there are x geese and y goats in the meadow.

Each goose has 2 legs, so the total number of goose legs is 2x. Each goat has 4 legs, so the total number of goat legs is 4y.

According to the problem, the total number of legs counted by Dima is 10. Therefore, we can write the equation:

2x + 4y = 10

To find the possible values of x and y, we can solve this equation.

Solving the Equation

Let's solve the equation using a method called substitution.

From the equation 2x + 4y = 10, we can isolate x in terms of y:

2x = 10 - 4y x = (10 - 4y) / 2 x = 5 - 2y

Now we can substitute this expression for x in the equation 2x + 4y = 10:

2(5 - 2y) + 4y = 10 10 - 4y + 4y = 10 10 = 10

The equation simplifies to 10 = 10, which is always true. This means that there are infinitely many solutions to the equation.

Conclusion

Based on the given information, we cannot determine the exact number of geese and goats in the meadow. There are infinitely many possible combinations of geese and goats that could have a total of 10 legs.