Question

Решите задачу :В стаде 8 овец. Первая съедает копну сена за 1 день, вторая -за 2 дня, восьмая - за 8 дней. Кто быстрее съест копну сена: две первые овцы или все остальные вместе? Пажалуйста пажалуйста решите

Answer 1

Ответ:

первые две

Пошаговое объяснение:

!!!!!!!!!!!!!!!!!!

Answer 2

Problem Analysis

The problem states that there are 8 sheep in a flock, and each sheep eats a pile of hay in a certain number of days. The first sheep eats the pile in 1 day, the second sheep eats it in 2 days, and so on, with the eighth sheep eating it in 8 days. The question is whether the first two sheep eat the pile faster or if the remaining sheep eat it faster when they eat together.

Solution

To solve this problem, we need to calculate the total amount of hay eaten by the first two sheep and compare it to the total amount of hay eaten by the remaining six sheep.

Let's start by calculating the amount of hay eaten by the first two sheep. The first sheep eats the entire pile in 1 day, and the second sheep eats the entire pile in 2 days. Therefore, the total amount of hay eaten by the first two sheep is the sum of the hay eaten by each sheep individually.

Next, let's calculate the amount of hay eaten by the remaining six sheep. Each of these sheep eats the entire pile in 8 days. Since there are six sheep, the total amount of hay eaten by the remaining sheep is the product of the hay eaten by each sheep individually multiplied by the number of sheep.

Now, we can compare the total amount of hay eaten by the first two sheep to the total amount of hay eaten by the remaining six sheep to determine which group eats the pile faster.

Calculation

Let's calculate the total amount of hay eaten by the first two sheep:

- The first sheep eats the entire pile in 1 day. - The second sheep eats the entire pile in 2 days.

Therefore, the total amount of hay eaten by the first two sheep is 1 + 2 = 3 piles of hay.

Now, let's calculate the total amount of hay eaten by the remaining six sheep:

- Each of the remaining six sheep eats the entire pile in 8 days. - There are six remaining sheep.

Therefore, the total amount of hay eaten by the remaining six sheep is 8 * 6 = 48 piles of hay.

Conclusion

The first two sheep eat a total of 3 piles of hay, while the remaining six sheep eat a total of 48 piles of hay. Therefore, the remaining six sheep eat the pile of hay faster than the first two sheep.

Note: The solution provided above is based on the information given in the problem statement. However, it is important to note that the problem statement does not provide any information about the size or weight of the hay pile, so the comparison of the eating speed is based solely on the number of days it takes for each sheep to eat the pile.