Question

В стаде 8 овец. Первая овца сьедает копну сена за 1 день, вторая за 2 дня, третья - за три и т.д., восьмая - за 8 дней. Кто быстрее сьест копну сена: две первые овцы или остальные овцы вместе?

Answer 1

две первые съедят быстрее

Answer 2

Problem Analysis

We are given a scenario where there are 8 sheep, and each sheep eats a pile of hay in a certain number of days. The first sheep eats the pile in 1 day, the second sheep eats it in 2 days, the third sheep eats it in 3 days, and so on, until the eighth sheep eats it in 8 days. We need to determine whether the first two sheep together eat the pile of hay faster than the remaining sheep combined.

Solution

To solve this problem, we need to calculate the total amount of hay consumed by the first two sheep and compare it to the total amount consumed by the remaining six sheep.

Let's calculate the total amount of hay consumed by the first two sheep: - The first sheep eats the pile in 1 day, so it consumes 1/1 = 1 unit of hay. - The second sheep eats the pile in 2 days, so it consumes 1/2 = 0.5 units of hay. - Therefore, the total amount of hay consumed by the first two sheep is 1 + 0.5 = 1.5 units.

Now, let's calculate the total amount of hay consumed by the remaining six sheep: - The third sheep eats the pile in 3 days, so it consumes 1/3 = 0.33 units of hay. - The fourth sheep eats the pile in 4 days, so it consumes 1/4 = 0.25 units of hay. - The fifth sheep eats the pile in 5 days, so it consumes 1/5 = 0.2 units of hay. - The sixth sheep eats the pile in 6 days, so it consumes 1/6 = 0.17 units of hay. - The seventh sheep eats the pile in 7 days, so it consumes 1/7 = 0.14 units of hay. - The eighth sheep eats the pile in 8 days, so it consumes 1/8 = 0.13 units of hay. - Therefore, the total amount of hay consumed by the remaining six sheep is 0.33 + 0.25 + 0.2 + 0.17 + 0.14 + 0.13 = 1.22 units.

Comparing the total amounts of hay consumed, we can see that the first two sheep consume 1.5 units of hay, while the remaining six sheep consume 1.22 units of hay. Therefore, the first two sheep eat the pile of hay faster than the remaining sheep combined.

Answer

The first two sheep, when combined, eat the pile of hay faster than the remaining six sheep combined.