Question

Вместе у клоунов Бома и Бима было 20 воздушных шаров красных и зелёных если ты дашь мне 2 зелёных а я отдам тебе один красный то у нас будет поровну шариков сказал бом сколько воздушных шаров было у каждого клоуна

Answer 1

У Бома: 19 шаров
У Бима: 21 шар

Answer 2

Solution:

To solve this problem, we can use a simple algebraic approach. Let's denote the number of red balloons as R and the number of green balloons as G. We are given that the total number of balloons is 20, so we have the equation:

R + G = 20

We are also given the condition that if you give me 2 green balloons and I give you 1 red balloon, then we will have an equal number of balloons. This gives us the equation:

(G - 2) + 1 = (R + 1)

Let's solve these equations to find the values of R and G.

First, we can rewrite the second equation as:

G - 1 = R + 1

Now, we can substitute the value of R from the first equation into the second equation:

G - 1 = (20 - G) + 1

Solving for G:

2G = 20

G = 10

Now that we have the value of G, we can find the value of R using the first equation:

R + 10 = 20

R = 10

So, each clown had 10 red balloons and 10 green balloons.

Therefore, each clown had 10 balloons of each color.