Question

319. Из одной и той же исходной точки по кругу одновременно с разной скоростью побежали дети. Миша пробегает один круг за 4 мин, Сережа - за 3 мин, а Нурлан - за 6 мин. Через сколько минут мальчики встретятся? Можно условие ​

Answer 1

Ответ:

Задача из учебника 5 класса

Чтобы узнать через сколько минут ребята встретятся найдем

найдем наименьшее общее кратное чисел 3,4,и 6

разложим на множители каждое число

3=1*3

4=2*2

6=2*3

НОК (3;4;6)=2*3*2=12

Значит мальчики встретятся через 12 мин.

Миша пробежит 12:4=3 круга

Сережа 12:3=4 круга

Нурлан 12:6=2 круга

Answer 2

Відповідь:

Відповідь:

через 1хв, тобто 60с, тому что

12 = 2 * 2 * 3

15 = 3 * 5

20 = 2 * 2 * 5

НСК = 2 * 2 * 3 * 5 = 60 (с)

Answer 3

Problem Analysis

In this problem, we are given that three children, Misha, Sereja, and Nurlan, start running from the same point on a circular track simultaneously but at different speeds. We are also given the time it takes for each child to complete one lap around the track. We need to determine how long it will take for the children to meet again at the starting point.

Solution

To solve this problem, we need to find the least common multiple (LCM) of the times it takes for each child to complete one lap around the track. The LCM will give us the time it takes for all three children to meet again at the starting point.

Let's find the LCM of the given times:

- Misha takes 4 minutes to complete one lap. - Sereja takes 3 minutes to complete one lap. - Nurlan takes 6 minutes to complete one lap.

To find the LCM, we can list the multiples of each time until we find a common multiple:

Multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, ...

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, ...

Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, ...

From the lists above, we can see that the least common multiple of 4, 3, and 6 is 12.

Therefore, the children will meet again at the starting point after 12 minutes.

Answer

The children will meet again at the starting point after 12 minutes.