Question

1) 4/9+3/8= 2) 7/12-3/8=​

Answer 1

.....................................

Answer 2

Ответ:

$\frac{4}{9}+ \frac{3}{8}= \frac{4*8}{9*8}+ \frac{3*9}{8*9}=\frac{32}{72}+ \frac{27}{72} =\frac{32+27}{72}=\frac{59}{72}$

$\frac{7}{12}- \frac{3}{8}= \frac{7*2}{12*2}- \frac{3*3}{8*3}= \frac{14}{24}- \frac{9}{24} =\frac{14-9}{24} =\frac{5}{24}$

Пошаговое объяснение:

Answer 3

1) To calculate the sum of 4/9 and 3/8, we need to find a common denominator. The least common multiple of 9 and 8 is 72. Therefore, we can rewrite the fractions with a common denominator of 72:

4/9 = (4/9) * (8/8) = 32/72 3/8 = (3/8) * (9/9) = 27/72

Now, we can add the fractions:

32/72 + 27/72 = (32 + 27)/72 = 59/72

So, the sum of 4/9 and 3/8 is 59/72.

2) To calculate the difference between 7/12 and 3/8, we also need to find a common denominator. The least common multiple of 12 and 8 is 24. So, we can rewrite the fractions with a common denominator of 24:

7/12 = (7/12) * (2/2) = 14/24 3/8 = (3/8) * (3/3) = 9/24

Now, we can subtract the fractions:

14/24 - 9/24 = (14 - 9)/24 = 5/24

So, the difference between 7/12 and 3/8 is 5/24.

In summary: 1) 4/9 + 3/8 = 59/72 2) 7/12 - 3/8 = 5/24