Question

В одном классе 27 учеников,в другом-на 6 человек меньше.За билеты в цирк первый класс заплатил на 960р больше,чем второй.Сколько заплатил за билеты каждый класс,если цена билетов была одинаковой?

Answer 1

1) 27 - 6 = 21 человек во 2 классе

2) 960 : 6 = 160 рублей стоит 1 билет

3) 27 х 160 = 4320 рублей заплатил за билеты 1 класс

4) 21 х 160 = 3360 рублей заплатил за билеты 2 класс

Answer 2

27-6=21 человек во 2 классе

960:6=160 рублей-цена 1 билета

27*160=4320 заплатил 1 класс

21*160=3360 заплатил 2 класс 

Answer 3

Problem Analysis

We are given two classes, one with 27 students and the other with 6 fewer students. The first class paid 960 rubles more for circus tickets than the second class. We need to determine the amount paid by each class for the tickets, assuming the ticket prices were the same.

Solution

Let's assume the ticket price for both classes is x rubles.

The total amount paid by the first class can be calculated by multiplying the number of students (27) by the ticket price (x). Similarly, the total amount paid by the second class can be calculated by multiplying the number of students (27 - 6 = 21) by the ticket price (x).

According to the given information, the total amount paid by the first class is 960 rubles more than the total amount paid by the second class.

Using this information, we can set up the following equation:

27x = 21x + 960

Now, let's solve this equation to find the value of x.

27x - 21x = 960 6x = 960 x = 960 / 6 x = 160

Therefore, the ticket price for each class is 160 rubles.

To find the total amount paid by each class, we can multiply the ticket price by the number of students in each class.

For the first class: Total amount paid = 160 rubles * 27 students = 4320 rubles

For the second class: Total amount paid = 160 rubles * 21 students = 3360 rubles

Answer

Each class paid 160 rubles per ticket. The first class paid a total of 4320 rubles for the tickets, while the second class paid a total of 3360 rubles for the tickets.