Question

(7/19z-1/6)*3/16=3/16

Answer 1

Ответ:

19\6

Пошаговое объяснение:

на фото ниже

Answer 2

(7/19z - 1/6) * 3/16 = 3/16

To solve this equation, we will use the distributive property to multiply 3/16 by each term within the parentheses:

(7/19z * 3/16) - (1/6 * 3/16) = 3/16

Now let's simplify each term separately: (7/19z * 3/16) = (7/19 * 3)/(z * 16) = 21/304z

(1/6 * 3/16) = (1/6 * 3)/(16) = 3/96 = 1/32

Now we can rewrite the equation: 21/304z - 1/32 = 3/16

To combine the terms with different denominators, we need to find a common denominator. In this case, the least common multiple of 304 and 32 is 608. Therefore, we need to multiply the first term by 2/2 and the second term by 19/19 to get the same denominator:

(21/304z * 2/2) - (1/32 * 19/19) = 42/608z - 19/608 = 3/16

Now we can combine the terms: 42/608z - 19/608 = 3/16

To isolate z, we will subtract 42/608z from both sides of the equation:

-19/608 = 3/16 - 42/608z

To simplify, let's find a common denominator for 16 and 608: 16 * 38 = 608

Now we can rewrite the equation: -19/608 = (3 * 38)/608 - 42/608z

Combining the terms on the right side: -19/608 = 114/608 - 42/608z

Now, to isolate z, we will subtract 114/608 from both sides:

-19/608 - 114/608 = -42/608z

-133/608 = -42/608z

Finally, to solve for z, we will divide both sides by -42/608:

-133/608 / -42/608 = z

Simplifying: -133/42 = z

Therefore, the solution is z = -133/42.