Question

Аул расположен между станцией и дачным поселком на расстоянии 4 км от станции. Из аула в сторону дачного поселка вышел пешеход со скоростью 75м/мин. Через 0,5 ч со станции в том же направлении выехал велосипед со скоростью 200м/мин. Через сколько минут велосипедист догонит пешехода?

Answer 1

0,5 ч = 30 мин
4 км = 4000 м
75*30=2250 м прошел пешеход за 30 минут
4000+2250 = 6250 м было между ними до начала движения
200-75=125 м/мин - общая скорость
6250/125= 50 минут
Ответ: Через 50 минут они встретятся

Answer 2

Problem Analysis

We are given the following information: - There is a village (аул) located 4 km away from a train station and a dacha settlement. - A pedestrian starts walking from the village towards the dacha settlement at a speed of 75 m/min. - After 0.5 hours (30 minutes), a cyclist starts riding from the train station towards the dacha settlement at a speed of 200 m/min.

We need to determine how many minutes it will take for the cyclist to catch up to the pedestrian.

Solution

To solve this problem, we can use the concept of relative speed. The relative speed between the cyclist and the pedestrian is the difference in their speeds.

Let's calculate the relative speed: - The speed of the cyclist is 200 m/min. - The speed of the pedestrian is 75 m/min.

Therefore, the relative speed between the cyclist and the pedestrian is 200 m/min - 75 m/min = 125 m/min.

Since the cyclist starts 30 minutes after the pedestrian, we need to calculate the distance covered by the pedestrian in those 30 minutes.

The distance covered by the pedestrian in 30 minutes is: Distance = Speed × Time Distance = 75 m/min × 30 min = 2250 meters.

Now, we can calculate the time it will take for the cyclist to catch up to the pedestrian.

Time = Distance / Relative Speed Time = 2250 meters / 125 m/min = 18 minutes.

Therefore, the cyclist will catch up to the pedestrian in 18 minutes.

Answer

The cyclist will catch up to the pedestrian in 18 minutes.

Note: The sources provided do not contain relevant information for this specific problem.