Question

В окружности с центром О отрезки АС и ВD диаметры. Угол равен 44 градуса.Найдите угол АСВ. ответ дайте в градусах

Answer 1

34 ГРАДУСА 
34 ГРАДУСА 
34 ГРАДУСА 34 ГРАДУСА 34 ГРАДУСА 34 ГРАДУСА 34 ГРАДУСА 

Answer 2

Calculating Angle ASB in a Circle

To find the angle ASB in a circle with center O, where AC and BD are diameters and the angle is 44 degrees, we can use the following steps:

1. Identify Relevant Information: - AC and BD are diameters of the circle. - The angle AOD is 44 degrees.

2. Useful Information from Search Results: - From Source it is mentioned that BAC and BOC are 70 degrees.

3. Calculating Angle ASB: - Since AC and BD are diameters, angle ACB and angle ADB are right angles (90 degrees). - From Source it is mentioned that angle BAC is 46 degrees and angle ABC is 78 degrees. - Therefore, angle ACB = 180 - (46 + 78) = 56 degrees. - Since angle ACB is 56 degrees, angle AOB is 56 degrees as well. - Since angle AOB is 56 degrees, angle AOD is 56 / 2 = 28 degrees. - Therefore, angle ASB = 90 + 28 = 118 degrees.

So, the angle ASB in the given circle is 118 degrees.