Question

Первое слагаемое равно 5460, второе - больше него на 545 десятков, третье- на 46 сотен больше второго,а четвёртое - равно сумме первых трёх слагаемых.Найдите сумму всех четырёх слагаемых. помогите пожалуйста

Answer 1

5460-первое
5460+545*10=5460+5450=10910 второе
10910+46*100=10910+4600=15510 третье
5460+10910+15510=31880 четвертое

5460+10910+15510+31880=63760 или 31880*2=63760

Answer 2

#### Problem Analysis To find the sum of the four terms, we need to determine the values of each term based on the given information. Let's break down the problem step by step: 1. The first term is 5460. 2. The second term is 545 tens more than the first term. 3. The third term is 46 hundreds more than the second term. 4. The fourth term is the sum of the first three terms. #### Solution Let's calculate the values of each term: 1. The first term is 5460. 2. The second term is 545 tens more than the first term, which means it is 5450 + 5450 = 5995. 3. The third term is 46 hundreds more than the second term, which means it is 5995 + 46 * 100 = 10495. 4. The fourth term is the sum of the first three terms, which means it is 5460 + 5995 + 10495 = 21950. Therefore, the sum of all four terms is 21950. #### Answer The sum of all four terms is **21950**. Please let me know if there's anything else I can help you with!