Question

Даю 30 балов! В ящике имеется 5 деталей, изготовленных заводом № 1 и 10 деталей, изготовленных заводом № 2. Сборщик последовательно вынимает из ящика детали одну за другой. Найти вероятность того, что второй будет извлечена деталь, изготовленная заводом № 1.

Answer 1

Ответ:

Пусть первой вынули детальку завода №1  

Вероятность этого 1/3  

Вероятность, что сразу после этого вынули детальку второго - 10/14  

Перемножаем  

 

Пусть первой вынули детальку завода №2  

Вероятность этого 2/3  

Вероятность, что сразу после этого вынули детальку первого - 5/14  

Перемножаем  

 

Складываем, получаем ответ

Пошаговое объяснение:

Answer 2

#### Problem Analysis We have a box containing a total of 15 parts, with 5 parts manufactured by Factory #1 and 10 parts manufactured by Factory #2. The assembler takes out the parts one by one. We need to find the probability that the second part taken out will be manufactured by Factory #1. #### Solution To find the probability, we need to determine the total number of possible outcomes and the number of favorable outcomes. Let's break down the problem step by step: 1. Total number of possible outcomes: - The assembler takes out one part at a time, so the total number of possible outcomes is the total number of parts in the box, which is 15. 2. Number of favorable outcomes: - The probability of the second part being manufactured by Factory #1 depends on the outcome of the first part. If the first part is manufactured by Factory #1, then there are 4 parts left from Factory #1 and 10 parts left from Factory #2. So, the number of favorable outcomes is 4. 3. Probability calculation: - The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. - Therefore, the probability that the second part taken out will be manufactured by Factory #1 is **4/15**. #### Answer The probability that the second part taken out will be manufactured by Factory #1 is **4/15**. Note: The sources provided do not contain relevant information for this specific question.