Question

Имеется два сплава.. первый содержит 10% никеля,второй 25% никеля. из этих двух сплавов получили третий сплав массой 150кг,содержащий 20% никеля. на сколько кг масса первого сплава меньше массы второго? Просьба:не копировать решение с похожей задачи!!!!

Answer 1

Х,у-массы сплавов
х+у=150
х=150-у
0,1х+0,25у=0,2*150
0,1х+0,25у=30
0,1(150-у)+0,25у=30
15-0,1у+0,25у=30
0,15у=15
у=15/0,15=1500/15=100кг-второй
150-50=50кг-первый
100-50=50кг-на столько

Answer 2

Problem Analysis

We have two alloys, one containing 10% nickel and the other containing 25% nickel. A third alloy is formed by combining these two alloys, and it has a mass of 150 kg and contains 20% nickel. We need to find the difference in mass between the first and second alloys.

Solution

Let's assume the mass of the first alloy is x kg. Therefore, the mass of the second alloy would be 150 - x kg.

To find the difference in mass between the first and second alloys, we need to subtract the mass of the second alloy from the mass of the first alloy:

x - (150 - x)

Now, let's calculate the value of x.

Calculation

To calculate the value of x, we can use the equation that relates the percentage of nickel in the alloys to their masses.

The equation is as follows:

(mass of alloy 1 * percentage of nickel in alloy 1) + (mass of alloy 2 * percentage of nickel in alloy 2) = (mass of alloy 3 * percentage of nickel in alloy 3)

Substituting the given values:

(x * 10%) + ((150 - x) * 25%) = (150 kg * 20%)

Simplifying the equation:

0.1x + 0.25(150 - x) = 0.2 * 150

Solving for x:

0.1x + 37.5 - 0.25x = 30

0.15x = 30 - 37.5

0.15x = -7.5

x = -7.5 / 0.15

x = 50

Answer

The mass of the first alloy is 50 kg. Therefore, the mass of the second alloy is 150 - 50 = 100 kg.

Hence, the mass of the first alloy is 50 kg less than the mass of the second alloy.