Question

Сравни время движения двух спутников, если первый спутник Земли делает оборот за 1 час 40 минут, а второй - за 6000 секунд.Помогите решить задачу пожалуйста!!!

Answer 1

6000= 1 час 40
1 час 40=1 час 40 

Answer 2

Comparing the Orbital Periods of Two Satellites

To compare the time it takes for two satellites to complete one orbit, we can use the formula:

Orbital Period (T) = 2 * π * √(a^3 / GM)

Where: - T = Orbital Period - π ≈ 3.14159 - a = Semi-major axis of the satellite's orbit - G = Gravitational constant - M = Mass of the Earth

Calculating the Orbital Period of the First Satellite

Given that the first satellite completes one orbit in 1 hour and 40 minutes, we need to convert this time to minutes for calculation.

1 hour = 60 minutes So, 1 hour 40 minutes = 60 + 40 = 100 minutes

Let's assume the semi-major axis of the first satellite's orbit is 'a' and the mass of the Earth is 'M'.

Using the formula, we can calculate the orbital period (T1) of the first satellite.

Calculating the Orbital Period of the Second Satellite

For the second satellite, it completes one orbit in 6000 seconds.

Let's assume the semi-major axis of the second satellite's orbit is 'b' and the mass of the Earth is 'M'.

Using the formula, we can calculate the orbital period (T2) of the second satellite.

Comparing the Orbital Periods

Now that we have calculated the orbital periods of both satellites, we can compare them to see the difference in their orbital times.

Please note that the specific values of 'a', 'b', and 'M' are required to calculate the exact orbital periods of the satellites.

Let's proceed with the calculations and compare the orbital periods of the two satellites.