Question

Найдите сумму. 4 5/9+ (-6 1/9); -3 5/7+6 9/14; 1 8/11+(-7 8/11)

Answer 1

4 5/9 - 6 1/9= -(5 10/9-4 5/9)= -1 5/9

-3 5/7 + 6 9/14= 5 23/14-3 10/14= 2 13/14

1 8/11-7 8/11=-6

Answer 2

4 5/9+ (-6 1/9)= 14/9
-3 5/7+6 9/14=12/7
1 8/11+(-7 8/11)= -48/11

Answer 3

I can help you with math problems. Here is the detailed solution for your query.

The sum of the three fractions is:

$$4 \frac{5}{9} + (-6 \frac{1}{9}) + (-3 \frac{5}{7} + 6 \frac{9}{14}) + (1 \frac{8}{11} + (-7 \frac{8}{11}))$$

To add or subtract fractions, we need to have a common denominator. The least common multiple of 9, 7, and 11 is 693. So we multiply each fraction by a factor that will make the denominator 693.

$$\frac{63}{63} \times 4 \frac{5}{9} + \frac{77}{77} \times (-6 \frac{1}{9}) + (\frac{99}{99} \times (-3 \frac{5}{7}) + \frac{49}{49} \times 6 \frac{9}{14}) + (\frac{63}{63} \times 1 \frac{8}{11} + \frac{63}{63} \times (-7 \frac{8}{11}))$$

$$= \frac{2520 + 315}{693} + \frac{-4620 - 77}{693} + (\frac{-1980 - 495}{693} + \frac{2940 + 441}{693}) + (\frac{630 + 504}{693} + \frac{-4410 - 504}{693})$$

$$= \frac{2835}{693} + \frac{-4697}{693} + (\frac{-2475}{693} + \frac{3381}{693}) + (\frac{1134}{693} + \frac{-4914}{693})$$

Now we can add or subtract the numerators and keep the same denominator.

$$= \frac{2835 - 4697 - 2475 + 3381 + 1134 - 4914}{693}$$

$$= \frac{-4736}{693}$$

We can simplify this fraction by dividing both the numerator and the denominator by the greatest common factor, which is 77.

$$= \frac{-4736 \div 77}{693 \div 77}$$

$$= \frac{-61}{9}$$

Therefore, the final answer is:

$$4 \frac{5}{9} + (-6 \frac{1}{9}) + (-3 \frac{5}{7} + 6 \frac{9}{14}) + (1 \frac{8}{11} + (-7 \frac{8}{11})) = -\frac{61}{9}$$

I hope this helps. If you have any other math questions, feel free to ask me.Ответь+подробно.+Найдите+сумму.+4+5/9++(-6+1/9);+-3+5/7+6+9/14;+1+8/11+(-7+8/11)