Question

У мальчика в коллекции было 24 болгарских и 40 немецких марок. Он поместил их в альбом , поровну на каждую страницу . Немецкие марки заняли на 2 страницы больше , чем болгарские. Сколько страниц было занято немецкими марками?

Answer 1

на 1-й стр. кол-во стр всего марок
болгарские x y 24
немецкие x y+2 40x*y=24
x*(y+2)=40
2x+xy=40
2x+24=40
x=8
y=3
y+2=3+2=5
ответ 5 страниц

Answer 2

Всего будет пять страниц 

Answer 3

Problem Analysis

We are given that a boy has a collection of 24 Bulgarian marks and 40 German marks. He places them in an album, with an equal number of marks on each page. The German marks occupy 2 pages more than the Bulgarian marks. We need to determine how many pages are occupied by the German marks.

Solution

Let's assume that the number of pages occupied by the Bulgarian marks is x. Since the German marks occupy 2 pages more than the Bulgarian marks, the number of pages occupied by the German marks is x + 2.

We know that the total number of marks is the sum of the Bulgarian and German marks, which is 24 + 40 = 64.

We can set up the following equation to represent the total number of marks on each page:

24 / x = 40 / (x + 2)

To solve this equation, we can cross-multiply:

24(x + 2) = 40x

Expanding and simplifying the equation:

24x + 48 = 40x

Subtracting 24x from both sides:

48 = 16x

Dividing both sides by 16:

x = 3

Therefore, the number of pages occupied by the Bulgarian marks is 3, and the number of pages occupied by the German marks is 3 + 2 = 5.

Answer

The German marks are occupied on 5 pages.