Question

(x^2-1)+2(x^2-1)-80=0

Answer 1

Здесь проще Т=х^2-1
Т+2Т-80=0
3Т=80
Т1=-корень(80/3)
Т2=корень(80/3)

При Т1:
Х^2=-корень(80/3)+1
Так как это однозначно меньше 0, то решений нет

При Т2:
Х^2=корень(80/3)+1
Х1=-корень(корень(80/3)+1)
Х2=корень(корень(80/3)+1)

Ну в принципе можно на калькуляторе подсчитать приближенные значения

Answer 2

To solve the equation $(x^2 - 1) + 2(x^2 - 1) - 80 = 0$, you can follow these steps:

1. Combine like terms:

   $(x^2 - 1) + 2(x^2 - 1) - 80 = 0$

   $x^2 - 1 + 2x^2 - 2 - 80 = 0$

   $3x^2 - 83 = 0$

2. Add 83 to both sides of the equation to isolate the $3x^2$ term:

   $3x^2 - 83 + 83 = 0 + 83$

   $3x^2 = 83$

3. Divide both sides by 3 to solve for $x^2$:

   $\frac{3x^2}{3} = \frac{83}{3}$

   $x^2 = \frac{83}{3}$

4. Take the square root of both sides to solve for $x$. Remember to consider both the positive and negative square roots:

   $x = \pm \sqrt{\frac{83}{3}}$

So, the solutions for $x$ are $x = \sqrt{\frac{83}{3}}$ and $x = -\sqrt{\frac{83}{3}}$.