Question

A)4\5x=16 B)5\14x=13 1\3

Answer 1

А: 4:5х=16
5х=4:16
5х=0,25
х=0,25:5
х=0,05

Answer 2

А) 4/5х=16
Х=16:4/5
Х=1/20
В)5/14х=13 1/3
Х=13 1/3:5/14
Х=112/3 может можно сократить но я хз

Answer 3

To solve for x in each of these equations, you can isolate x by performing the necessary algebraic operations. Let's solve each equation step by step:

A) $\frac{4}{5}x = 16$

To solve for x, you can first get rid of the fraction by multiplying both sides of the equation by the reciprocal of $\frac{4}{5}$, which is $\frac{5}{4}$:

$\frac{5}{4} \cdot \frac{4}{5}x = 16 \cdot \frac{5}{4}$

This simplifies to:

$x = 16 \cdot \frac{5}{4}$

Now, calculate the right-hand side:

$x = 20$

So, the solution to equation A is $x = 20$.

B) $\frac{5}{14}x = \frac{13}{3}$

To solve for x, you can again get rid of the fraction by multiplying both sides of the equation by the reciprocal of $\frac{5}{14}$, which is $\frac{14}{5}$:

$\frac{14}{5} \cdot \frac{5}{14}x = \frac{13}{3} \cdot \frac{14}{5}$

This simplifies to:

$x = \frac{13}{3} \cdot \frac{14}{5}$

Now, calculate the right-hand side:

$x = \frac{182}{15}$

So, the solution to equation B is $x = \frac{182}{15}$.