Question

1)2x-(5x-6)=7+(x-1)2)3x-1=2x-(4-x)3)2(x-3)=-3(x+2)

Answer 1

2x-(5x-6)=7+(x-1)
2x-5x+6=7+x-1
-3x+6=6+x
-3=x
-3x-x=0
-4x=0
x=0

Answer 2

Sure, I'd be happy to help you solve these equations:

1. $2x - (5x - 6) = 7 + (x - 1)$

First, distribute the negative sign:

$2x - 5x + 6 = 7 + x - 1$

Combine like terms:

$-3x + 6 = x + 6$

Subtract $x$ from both sides:

$-4x + 6 = 6$

Subtract 6 from both sides:

$-4x = 0$

Divide by -4:

$x = 0$

2. $3x - 1 = 2x - (4 - x)$

First, distribute the negative sign:

$3x - 1 = 2x - 4 + x$

Combine like terms:

$3x - 1 = 3x - 4$

Subtract $3x$ from both sides:

$-1 = -4$

This is not possible. There is no solution to this equation.

3. $2(x - 3) = -3(x + 2)$

First, distribute on both sides:

$2x - 6 = -3x - 6$

Add $3x$ to both sides:

$5x - 6 = -6$

Add 6 to both sides:

$5x = 0$

Divide by 5:

$x = 0$

So, the solutions are:

1. $x = 0$
2. No solution
3. $x = 0$