Question

1)y + 20 = -y2)2(x - 2) - 1 = 5(x - 2) - 7​

Answer 1

1) у+у=-20

2у=-20|:2

у=-10

2) 2х-4-1=5х-10-7

2х-5х=4+1-10-7

-3х=-12|:(-3)

х=4

Answer 2

Sure, let's solve the given equations step by step:

Equation 1: $y + 20 = -y$

To solve for $y$, you can first add $y$ to both sides of the equation to get rid of the $y$ term on the right side:

$y + y + 20 = -y + y$ $2y + 20 = 0$

Next, subtract 20 from both sides:

$2y = -20$

Finally, divide by 2 to isolate $y$:

$y = -10$

Equation 2: $2(x - 2) - 1 = 5(x - 2) - 7$

First, distribute the 2 and 5 on the left and right sides of the equation, respectively:

$2x - 4 - 1 = 5x - 10 - 7$

Combine like terms on both sides:

$2x - 5 = 5x - 17$

Next, move the $5x$ term to the left side by subtracting $5x$ from both sides:

$2x - 5 - 5x = -17$

$-3x - 5 = -17$

Now, add 5 to both sides:

$-3x - 5 + 5 = -17 + 5$

$-3x = -12$

Finally, divide by -3 to solve for $x$:

$x = 4$

So, the solutions to the given equations are $x = 4$ and $y = -10$.