Question

1. 6 5/13+2 8/13 2. 5 4/7+3 6/7 3.1-15/9 4.8-3 4/9 5.7 3/8-2 5/8 6.14 15/32-9 19/32

Answer 1

1) = 8 13/13 = 9
2) = 8 10/7 = 9 3/7
3) = 9/9 - 15/9 = -6/9 = -2/3
4) = 7 9/9 - 3 4/9 = 4 5/9
5) = 6 11/8 - 2 5/8 = 4 6/8 = 4 3/4
6) = 13 47/32 - 9 19/32 = 4 28/32 = 4 7/8

Answer 2

Let's solve each of these arithmetic expressions step by step:

1. $6 \frac{5}{13} + 2 \frac{8}{13}$ To add these fractions, you need a common denominator, which is 13. So: $6 \frac{5}{13} + 2 \frac{8}{13} = 6 + 2 + \frac{5}{13} + \frac{8}{13} = 8 \frac{13}{13} = 9$.

2. $5 \frac{4}{7} + 3 \frac{6}{7}$ Again, you need a common denominator, which is 7: $5 \frac{4}{7} + 3 \frac{6}{7} = 5 + 3 + \frac{4}{7} + \frac{6}{7} = 8 \frac{10}{7} = 9 \frac{3}{7}$.

3. $1 - \frac{15}{9}$ To subtract fractions, you need a common denominator, which is 9: $1 - \frac{15}{9} = 1 - \frac{5}{3}$. Now, subtract the fractions: $1 - \frac{5}{3} = \frac{3}{3} - \frac{5}{3} = -\frac{2}{3}$.

4. $8 - \frac{3}{9}$ Again, you need a common denominator, which is 9: $8 - \frac{3}{9} = 8 - \frac{1}{3}$. Now, subtract the fractions: $8 - \frac{1}{3} = \frac{24}{3} - \frac{1}{3} = \frac{23}{3}$.

5. $7 \frac{3}{8} - 2 \frac{5}{8}$ To subtract these fractions, you need a common denominator, which is 8: $7 \frac{3}{8} - 2 \frac{5}{8} = 7 - 2 + \frac{3}{8} - \frac{5}{8} = 5 - \frac{2}{8} = 5 - \frac{1}{4} = 4 \frac{3}{4}$.

6. $14 \frac{15}{32} - 9 \frac{19}{32}$ Once again, you need a common denominator, which is 32: $14 \frac{15}{32} - 9 \frac{19}{32} = 14 - 9 + \frac{15}{32} - \frac{19}{32} = 5 - \frac{4}{32} = 5 - \frac{1}{8} = 4 \frac{7}{8}$