Question

(x-2)²+(y+1)²=1. (2;1),1​

Answer 1

Ответ:

это уравнение окружности

координаты точки по формуле будут=А(2;-1)R=1

Answer 2

It looks like you have a circle equation:

(x - 2)² + (y + 1)² = 1

This equation represents a circle centered at the point (2, -1) with a radius of 1 unit.

Now, you've given two points: (2, 1) and (1, ?). You seem to be asking for the y-coordinate of the point (1, ?) that lies on the circle. To find this, you can substitute x = 1 into the equation and solve for y:

(1 - 2)² + (y + 1)² = 1 (-1)² + (y + 1)² = 1 1 + (y + 1)² = 1

Now, subtract 1 from both sides:

(y + 1)² = 0

To solve for y, take the square root of both sides:

y + 1 = 0

Now, subtract 1 from both sides to isolate y:

y = -1

So, the y-coordinate of the point (1, ?) on the circle is -1. Therefore, the point (1, -1) lies on the circle defined by the equation.