Question

(y-4)(y+1)+3y=(y-1)(y+4)+2y

Answer 1

Ответ:

У=(25-4)=78(45)7521+6

Answer 2

Let's solve the equation step by step:

(y - 4)(y + 1) + 3y = (y - 1)(y + 4) + 2y

First, let's multiply out the expressions on both sides of the equation:

(y^2 - 3y - 4) + 3y = (y^2 + 3y - 4) + 2y

Now, simplify both sides by combining like terms:

y^2 - 3y - 4 + 3y = y^2 + 3y - 4 + 2y

Notice that the 3y and -3y on the left side cancel each other out, leaving us with:

y^2 - 4 = y^2 + 5y - 4

Now, let's subtract y^2 from both sides of the equation to eliminate the y^2 terms:

-4 = 5y

Next, divide both sides by 5 to solve for y:

-4/5 = y

So, the solution to the equation is:

y = -4/5