Question

двум классам поручено расчистить школьный каток длина которого 32 м а ширина 20 м.В одном классе 33 ученика а в другом-31.Сколько квадратных метров должны расчистить ученики каждого класса,если распределить работу по числу учеников?помогите плииз,плииз(((

Answer 1

32*20=640

33+31=64

640/64=10 КВ.М ОДИН УЧЕНИК

10*33=330 ОДИН КЛАСС

10*31=310 ДРУГОЙ КЛАСС

 

 

 

 

 

 

 

 

Answer 2

Calculation of the Area of the School Ice Rink

To calculate the area of the school ice rink, we need to multiply its length by its width. According to the information provided, the length of the ice rink is 32 meters, and the width is 20 meters.

Therefore, the area of the ice rink can be calculated as follows:

Area = Length x Width

Area = 32 meters x 20 meters

Area = 640 square meters

So, the total area of the school ice rink is 640 square meters.

Distribution of Work among the Students

In one class, there are 33 students, and in the other class, there are 31 students. To determine how many square meters each class should clear, we need to divide the total area of the ice rink by the number of students in each class.

For the first class with 33 students:

Area per student = Total area / Number of students

Area per student = 640 square meters / 33 students

Area per student ≈ 19.39 square meters

Therefore, each student in the first class should clear approximately 19.39 square meters of the ice rink.

For the second class with 31 students:

Area per student = Total area / Number of students

Area per student = 640 square meters / 31 students

Area per student ≈ 20.65 square meters

Therefore, each student in the second class should clear approximately 20.65 square meters of the ice rink.

Please note that these calculations assume an equal distribution of work among the students in each class.