Question

41+2,3y+1,3y=38 (6 класс)​

Answer 1

Ответ:

-0,8(3)

41+2,3у+1,3у=38

2,3у+1,3у=38-41

3,6у=-3

У=-3:3,6

У=-0,8(3)

Answer 2

It looks like you have an equation to solve for the variable $y$. Let's solve it step by step:

$41 + 2.3y + 1.3y = 38$

Combine like terms:

$41 + 3.6y = 38$

Subtract 41 from both sides to isolate the term with $y$:

$3.6y = 38 - 41$

Simplify the right side:

$3.6y = -3$

Now, divide both sides by 3.6 to solve for $y$:

$y = \frac{-3}{3.6}$

Simplify the fraction:

$y = -\frac{5}{6}$

So, the solution to the equation is $y = -\frac{5}{6}$.