Question

C)x^2-7x+6=0 d)x^2-11x+10=0​

Answer 1

Ответ:

x^2+7x+6=0

D=(7)^2-4*1*6=49-24=25.Корень из 25=5

x1= -7-5/2=-1

x2=-7+5/2=-6

Ответ: x1=-1; x2=-6

Пошаговое объяснение:

x^2+7x+6=0

D=(7)^2-4*1*6=49-24=25=5

x1= -7-5/2=-1

x2=-7+5/2=-6

Answer 2

It looks like you've provided two quadratic equations. To solve these equations, you can use the quadratic formula:

For a quadratic equation in the form of ax^2 + bx + c = 0, the quadratic formula is:

x = (-b ± √(b^2 - 4ac)) / (2a)

Let's use this formula to solve the given equations:

a) x^2 - 7x + 6 = 0

In this equation, a = 1, b = -7, and c = 6.

x = (-(-7) ± √((-7)^2 - 4(1)(6))) / (2(1)) x = (7 ± √(49 - 24)) / 2 x = (7 ± √25) / 2 x = (7 ± 5) / 2

So, the solutions for this equation are:

x1 = (7 + 5) / 2 = 12 / 2 = 6 x2 = (7 - 5) / 2 = 2 / 2 = 1

Therefore, the solutions to the equation x^2 - 7x + 6 = 0 are x = 6 and x = 1.

b) x^2 - 11x + 10 = 0

In this equation, a = 1, b = -11, and c = 10.

x = (-(-11) ± √((-11)^2 - 4(1)(10))) / (2(1)) x = (11 ± √(121 - 40)) / 2 x = (11 ± √81) / 2 x = (11 ± 9) / 2

So, the solutions for this equation are:

x1 = (11 + 9) / 2 = 20 / 2 = 10 x2 = (11 - 9) / 2 = 2 / 2 = 1

Therefore, the solutions to the equation x^2 - 11x + 10 = 0 are x = 10 and x = 1.