Question

A)4(х−2)+2(х+3)=10 B)3|x=96

Answer 1

Ответ:

Пошаговое объяснение:

a) 4(х−2)+2(х+3)=10

4x-8+2x+3=10

6x+11=10

6x=10-11

6x=-1

x=-1/6

b) 3|x|=96 |:3

|x|=32

x=+-32

Answer 2

Let's solve these equations step by step:

A) 4(x - 2) + 2(x + 3) = 10

First, distribute the coefficients on the left side of the equation:

4x - 8 + 2x + 6 = 10

Combine like terms:

6x - 2 = 10

Now, isolate the variable x by adding 2 to both sides of the equation:

6x - 2 + 2 = 10 + 2

6x = 12

Now, divide both sides by 6 to solve for x:

6x/6 = 12/6

x = 2

So, the solution to equation A) is x = 2.

B) 3|x| = 96

To solve for x in equation B), we need to consider two cases, one for when x is positive and one for when x is negative.

Case 1: x is positive

3x = 96

Now, divide both sides by 3 to solve for x:

3x/3 = 96/3

x = 32

Case 2: x is negative

3(-x) = 96

Now, distribute the negative sign:

-3x = 96

Divide both sides by -3 to solve for x:

(-3x)/(-3) = 96/(-3)

x = -32

So, there are two solutions to equation B):

x = 32 (when x is positive) x = -32 (when x is negative)